SPOJ.com - Problem RGB7001

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RGB7001 - 2 тооны нийлбэр

Өгөгдсөн бүхэл тооны нийлбэрийг ол.

Input

2 бүхэл тоо зайгаар тусгаарлагдан нэг мөрөнд өгөгдөнө.

Output

2 тооны нийлбэр.

Example

Input:
12 23

Output:
35

Submit solution!

Нэмсэн:	Bataa
Огноо:	2011-01-15
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2024-04-11 02:51:36
#include <bits/stdc++.h>
using namespace std;
int main () {
int a,b,c;
cin>>a;
cin>>b;
c=a+b;
cout << c << endl;
return 0;
}
huul

2024-03-28 05:27:52
#include <bits/stdc++.h>
using namespace std;
struct suragch{
int age;
double gpa;
string code,name;
string gender;
};
int main(){
int n;
int p=0,h=0,q=0;
cin>>n;
suragch s[n];
for(int i=0;i<n;i++){
cin>> s[i].code >> s[i].age >> s[i].gpa >> s[i].gender;
}
for(int i=0;i<n;i++){
if ( s[i].gender=="male"){
p++;
}
else {
h++;
}
}
cout<<"male"<<p<<";";
cout<<"female"<<h<<";";
for (int i=0;i<n;i++){
if (s[i].gpa>2.5){
q++;

}
}
cout<<"2.5 aas ih gpa tei suragch"<<" "<<q<<endl;
return 0;
}

2024-03-04 10:40:19
Take it easy
#include <iostream>
using namespace std;

int main() {
int a,b;
cin>>a>>b;
cout<<a+b;
return 0;
}

2024-02-21 02:53:20
import pygame
import time
import random

pygame.init()

# Define colors
white = (255, 255, 255)
yellow = (255, 255, 102)
black = (0, 0, 0)
red = (213, 50, 80)
green = (0, 255, 0)
blue = (50, 153, 213)

# Set display dimensions
dis_width = 800
dis_height = 600

# Define size of snake block and speed
snake_block = 10
snake_speed = 30

# Create display
dis = pygame.display.set_mode((dis_width, dis_height))
pygame.display.set_caption('Snake Game')

clock = pygame.time.Clock()

font_style = pygame.font.SysFont(None, 50)

def message(msg, color):
mesg = font_style.render(msg, True, color)
dis.blit(mesg, [dis_width / 6, dis_height / 3])

def gameLoop():
game_over = False
game_close = False

x1 = dis_width / 2
y1 = dis_height / 2

x1_change = 0
y1_change = 0

snake_list = []
length_of_snake = 1

foodx = round(random.randrange(0, dis_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, dis_height - snake_block) / 10.0) * 10.0

while not game_over:

while game_close == True:
dis.fill(blue)
message("You Lost! Press Q-Quit or C-Play Again", red)
pygame.display.update()

for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q:
game_over = True
game_close = False
if event.key == pygame.K_c:
gameLoop()

for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block
x1_change = 0

if x1 >= dis_width or x1 < 0 or y1 >= dis_height or y1 < 0:
game_close = True
x1 += x1_change
y1 += y1_change
dis.fill(blue)
pygame.draw.rect(dis, green, [foodx, foody, snake_block, snake_block])
snake_head = []
snake_head.append(x1)
snake_head.append(y1)
snake_list.append(snake_head)
if len(snake_list) > length_of_snake:
del snake_list[0]

for x in snake_list[:-1]:
if x == snake_head:
game_close = True

for segment in snake_list:
pygame.draw.rect(dis, black, [segment[0], segment[1], snake_block, snake_block])

pygame.display.update()

if x1 == foodx and y1 == foody:
foodx = round(random.randrange(0, dis_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, dis_height - snake_block) / 10.0) * 10.0
length_of_snake += 1

clock.tick(snake_speed)

pygame.quit()
quit()

gameLoop()

2024-02-03 05:17:04
.

Last edit: 2024-02-03 05:17:39

2024-01-12 04:33:27
#include <bits/stdc++.h>
using namespace std;
int ts(string a)
{
string b;
int s=0;
for (int i=0;i<a.size();i++)
{
s=s+(a[i]-'0');
}
return s;

}
int main(){
string a,b,c;
int d,e,m,t=0,l,g=1;
cin>>a>>m;
b=a;
while (t<=m)
{
c.clear();
int r=ts(a)%10;
a.push_back(r+'0');
for (int i=1;i<a.size();i++)
{
c.push_back(a[i]);
}
if (c==b)
{
cout<<t;
return 0;
}
else
{
g++;
t++;
a=c;
}
}
if(t>m)
cout<<0;
return 0;
}

2024-01-12 04:02:10
#include <bits/stdc++.h>
using namespace std;
int ts(string a)
{
string b;
int s=0;
for (int i=0;i<a.size();i++)
{
s=s+(a[i]-'0');
}
return s;

}
int main(){
string a,b;
int c,d,e,m;
b=a;
cin>>a>>m;
while (t<=m)
{
int r=ts(a)%10;
a.push
}
cout<<ts(a);
}

2023-12-22 05:28:04

2023-12-22 05:28:03

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7001 - 2 тооны нийлбэр

Input

Output

Example