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RGB7070 - Нийлбэр 1

Өгөгдсөн натурал тоо n хүртэлх натурал тоонуудын нийлбэрийг ол.

Давталт ашиглахгүй болно.

Input

Натурал тоо n өгөгдөнө.

Output

Нийлбэр

Example

Input:
10

Output:
55

Нэмсэн:Bataa
Огноо:2013-01-06
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2022-03-28 05:21:14
olsoooooodeeeeeeennaaaaaaa TvT
2022-03-25 07:02:41
#include<stdio.h>
int main()
{
int n, s, k, a;
scanf("%d", &n);
s=(1+n)*n/2;
printf("%d", s);
return 0;
}

ez
aripmetik progress lalruda
2022-03-16 11:30:54
int main oogiii
2022-03-07 04:36:42
dgdgd

Last edit: 2022-03-07 04:36:55
2021-12-11 13:04:27
a = int(input())
s = 0
for i in range(1,a+1):
s +=i
print(s)
ez
2021-11-18 03:51:09
9
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12
19
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1dont coy

Last edit: 2021-11-18 03:51:33
2021-10-11 12:30:38
#include <iostream>
using namespace std;

int main() {
int a;
cin>>a;
cout<<a*(a+1)/2;
return 0;
}

2021-05-27 18:09:47
#include <iostream>
using namespace std;

int main() {


int niilber,a,b,c,d,n,i;

cin >>n;
niilber = 0 ;
for (a =1 ; a<=n ; a ++ )
niilber +=a;


cout <<niilber;




return 0;
}
2021-01-17 10:56:08
;-;
2021-01-12 10:14:07
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,n,c;
cin>>a>>n;
c=a*n;
cout<<c;
return 0;
}
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