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RGB7111 - 11-д хуваагддаггүй |
Өгөгдсөн 4 тооны 11-д хууваагддаггүй тоонуудынх нь нийлбэрийг ол.
Input
Нэг мөрөнд Int төрлийн 4 тоо зайгаар тусгаарлагдан өгөгдөнө.
Output
11-д хуваагддаггүй тоонуудын нийлбэр.
Example
Input:
7 22 13 30
Output:
50
| Нэмсэн: | Bataa |
| Огноо: | 2011-05-27 |
| Хугацааны хязгаарлалт: | 1s |
| Эх кодын хэмжээний хязгаарлалт: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
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2023-04-04 08:35:47
#include <iostream> using namespace std; int main() { int a,b,c,d,i=0; cin >> a >> b >> c >> d; if (a %11==0){} else { i += a; } if (b %11==0){} else { i += b; } if (c %11==0){} else { i += c; } if (d %11==0){} else { i += d; } cout << i; return 0; } |
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2023-03-20 02:55:04
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2023-03-14 10:27:17
\ \\ \\\ \\\\ \\\\\ \\\\\\ \\\\\\\ \\\\\\\\ \\\\\\\\\ \\\\\\\\\\ \\\\\\\\\\\ |
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2023-03-13 07:05:34
g |
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2023-01-06 15:43:35
#include<stdio.h> int main() { int a, b, c, d, e; scanf("%d%d%d%d" ,&a ,&b ,&c ,&d); if(a%11==0) a=0; if(b%11==0) b=0; if(c%11==0) c=0; if(d%11==0) d=0; e=a+b+c+d; printf("%d" ,e); return 0; } |
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2022-12-02 06:12:30
#include <iostream> using namespace std; int main() { int a,b,c,d,cnt=0; cin>>a>>b>>c>>d; if (a%11!=0) cnt+=a; if (b%11!=0) cnt+=b; if (c%11!=0) cnt+=c; if (d%11!=0) cnt+=d; cout<<cnt; return 0; } |
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2022-11-14 09:51:15
a,b,c,d= [int(x) for x in input().split()] s=a+b+c+d if (a%11==0): s=s-a if(b%11==0): s=s-b if(c%11==0): s=s-c if(d%11==0): s=s-d print(s) python3.7.3 huul |
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2022-11-09 02:54:14
#include <stdio.h> main() { int a[4],i,niilber=0; for(i=0; i<4;i++) { scanf("%d",&a[i]); if(a[i]%11==0) a[i]=0; else niilber=niilber + a[i]; } printf("%d ",niilber); } |
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2022-11-07 08:21:48
#include <iostream> using namespace std; int main() { int a,b,c,s=0,d; cin>>a>>b>>c>>d; if (a%11!=0) {s+=a;} if (b%11!=0) {s+=b;} if (c%11!=0) {s+=c;} if (d%11!=0) {s+=d;} cout<<s; } good answer |
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2022-10-18 18:13:39
#include <stdio.h> int a,b,c,d,s=0; main() { scanf("%d %d %d %d",&a,&b,&c,&d); if(a%11==0) a=0; else s=s+a; if(b%11==0) b=0; else s=s+b; if(c%11==0) c=0; else s=s+c; if(d%11==0) d=0; else s=s+d; printf("%d",s); return 0; } |
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