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RGB7114 - Тэгш тоонууд YES

Гурван тоо өгөгдөнө. Тоо тэгш бол YES үгүй бол NO гэж хэвлэ.

Input

Int төрлийн 3 тоо нэг нэг мөрөнд өгөгдөнө.

Output

Тоо тус бүрийг шалгаад нэг нэг мөрөнд хариуг хэвлэ.

Example

Input:
3
4
5
Output:
NO
YES
NO


Нэмсэн:Bataa
Огноо:2011-05-31
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2023-01-17 15:05:04
a=int(input())
b=int(input())
c=int(input())
if(a%10%2==0):
print("YES")
else:
print("NO")
if(b%10%2==0):
print("YES")
else:
print("NO")
if(c%10%2==0):
print("YES")
else:
print("NO")
Delgerekh^^
2022-12-21 17:59:19
#include <stdio.h>
char * wether(int x){
if(x%2 == 0){
return "YES";
}else{
return "NO";
}
}
int main(void) {
// your code here
int a,b,c;
scanf("%d%d%d",&a,&b,&c);
char* f = wether(a);
char* s = wether(b);
char* t = wether(c);
printf("%s\n%s\n%s",f,s,t);
return 0;
}
2022-12-02 06:24:45
#include <iostream>
using namespace std;

int main() {

int a,b,c;
cin>>a>>b>>c;

if (a%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (b%2==0)
cout<<"YES\n";
else
cout<<"NO\n";

if (c%2==0)
cout<<"YES\n";
else
cout<<"NO\n";


return 0;
}
2022-11-07 08:28:27

#include <iostream>

using namespace std;

int main()
{
int a,b,c,s=0,d;
cin>>a>>b>>c;
if (a%2==0) {cout<<"YES"<<endl;}
else {cout<<"NO"<<endl;}
if (b%2==0) {cout<<"YES"<<endl;}
else {cout<<"NO"<<endl;}
if (c%2==0) {cout<<"YES"<<endl;}
else {cout<<"NO"<<endl;}
}
Good answer
2022-10-19 04:33:31
dig bick
2022-10-19 04:32:41
boov
2022-09-30 09:08:25
9-11-69
2022-05-17 14:37:00
a = int(input())
b = int(input())
c = int(input())
if(a%2==0):
print("YES")
else:
print("NO")
if(b%2==0):
print("YES")
else:
print("NO")
if(c%2==0):
print("YES")
else:
print("NO")
2022-04-27 10:31:45
.........................

Last edit: 2022-04-27 10:32:23
2022-04-01 03:42:39
egc ni ta nariig ni bodwol python dre neg murund bdson zaa gs teriig n unshihgu bur uur hureed suuj blaa
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