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RGB7210 - Тооны хүрд

Өгөгдсөн тооны хүрдийг дараах хэлбэрээр гарга.

Input

n натурал тоо өгөгдөнө. n<=10.

Output

n тооны хүрд нэг нэг мөрөнд хэвлэ.

Example

Input:
3

Output:
3*1=3
3*2=6
3*3=9
3*4=12
3*5=15
3*6=18
3*7=21
3*8=24
3*9=27
3*10=30
Submit solution!
Нэмсэн:Bataa
Огноо:2011-06-21
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE
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< Өмнөх 1  2  3  4  5  6  7 Дараагийн >
2022-01-06 09:26:20


Last edit: 2022-01-06 09:26:33
2021-11-12 16:55:51
#include<stdio.h>
int main()
{
int a,b=1;
scanf("%d",&a);
while(b<=10)
{
printf("%d*%d=%d\n",a,b,a*b);
b++;
}
}
mai suguudaa hhahhahhah
2021-10-11 08:45:15
#include<iostream>
using namespace std;
int main(){
int n,i;
cin>>n;
for(i=1; i<=10; i++){
cout<<n<<"*"<<i<<"="<<n*i<<endl;
}
}
2021-10-10 04:53:11



































































































































































































































































































































































































































































































































































































































































































































#include<stdio.h>
main()
{
int n,i;
scanf("%d",&n);
for(i=1; i<=10; i++)
printf("%d*%d=%d\n",n, i, n*i );
}

2021-05-24 12:47:41
#include <iostream>
using namespace std;

int main() {


int a,b,c,d,n,i,niilber=0,urjver=1,gurvaljin;


cin >>n;
for (i = 1 ; i<=10;i ++ ) {
cout<<n<<"*"<<i<<"="<<n*i<<endl ;








}
#include <iostream>
using namespace std;

int main() {


int a,b,c,d,n,i,niilber=0,urjver=1,gurvaljin;


cin >>n;
for (i = 1 ; i<=10;i ++ ) {
cout<<n<<"*"<<i<<"="<<n*i<<endl ;








}
2021-02-27 11:11:49
#include<stdio.h>
main()
{
int n,i;
scanf("%d",&n);
for(i=1; i<=10; i++)
printf("%d*%d=%d\n",n, i, n*i );
}
hicheegeere amjilt <3
2020-08-03 09:02:11
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa its so hard
2020-08-03 06:56:35
lol
2019-12-26 05:55:14
#include<iostream>
using namespace std;
main()
{
int n,m;
cin>>n;
for(int i=1;i<=10;i++)
cout<<n<<"*"<<i<<"="<<n*i<<endl;
}
2019-12-26 05:45:06
#include <iostream>
using namespace std;
int main () {
int n;
cin>>n;
for(int i=1;i<=10;i++)
cout<<n<<"*"<<i<<"="<<n*i<<"\n";
return 0;
}


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