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RGB7213 - Үржвэр нийлбэр 1

1*2+2*3+3*4+...+n*(n+1) нийлбэрийг ол.

Input

Натурал тоо өгөгдөнө.

Output

Нийлбэр

Example

Input:
5

Output:
70

Нэмсэн:Bataa
Огноо:2013-01-21
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2022-03-02 09:25:50
body chalky bn:(
2022-03-02 09:25:03
Ronaldo SUIIIIIIII

Last edit: 2022-03-02 09:25:31
2022-03-02 09:24:54
wyd
2022-03-02 09:24:46
oggey
2022-03-02 09:24:33
yes boon
2022-03-02 09:21:55
No
2021-11-19 00:12:49
int a, f=0;
Scanner cs = new Scanner(System.in);
a = cs.nextInt();
for(int i=1; i<=a; i++) {
f=f+(i*(i+1));
}
System.out.print(f);
2021-05-16 17:41:49
#include <iostream>
using namespace std;

int main(){
long n,s=1,i;
cin>>n;
cout<<(n*(n+1))/2+(n*(n+1)*(2*n+1))/6;
return 0;
}
2021-01-18 08:41:01
uursdu bod
2020-04-29 13:01:59
#include <iostream>
using namespace std;
int main(){
int a,f=0;
cin>>a;
for(int i=0;i<=a;i++){
f=f+(i*(i+1));
}cout<<f;
}
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