SPOJ.com - Problem RGB7217

Problem hidden

|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

RGB7217 - Давхар факториал

n!! - ыг ол. n тоо тэгш бол n хүртэлх тэгш тоонуудын үржвэр. n тоо сондгой бол n хүртэлх сондгой тоонуудын үржвэр. n=6 үед 2*4*6=48, n=7 үед 1*3*5*7=105

Input

Натурал тоо өгөгдөнө.

Output

Давхар факториал.

Example

Input:
6

Output:
48

Submit solution!

Нэмсэн:	Bataa
Огноо:	2013-01-21
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2022-05-26 02:01:41
ez

2022-04-04 08:30:04
#include<bits/stdc++.h>
main(){
int n,s=1,i,t=1;
scanf("%d",&n);
if(n%2==0){
for(i=2;i<=n;i=i+2)
s=s*i;
printf("%d",s);}
else if(n%2==1){
for(i=1;i<=n;i=i+2)
t=t*i;
printf("%d",t);
}
}
copy this archaaq amitan min

2021-06-02 09:38:44
https://www.youtube.com/watch?v=AROSUo35OPc

2021-03-23 10:58:47
|Notes:|
1. Don't post any source code here.|
2. Please be careful, leave short comments only. Don't spam here.|
3. For more discussion (hints, ideas, solutions) please visit our forum.|
4. Authors are allowed to delete the post and use html code here (e.g. to provide some useful links).|

Last edit: 2021-03-23 11:00:44

2020-11-01 02:58:53
#include<bits/stdc++.h>

using namespace std;

int main() {
int i, n, p=1;

cin>>n;
for(i=n; i>1; i=i-2){
p=p*i;
}

cout<<p<<endl;

return 0;
}

2020-01-09 04:41:43
h

Last edit: 2020-01-09 04:43:21

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7217 - Давхар факториал

Input

Output

Example