| Бодолт илгээх | Бүх бодолтууд | Шилдэг бодолтууд | Жагсаалт руу буцах |
RGB7237 - Арифметик дундаж |
Өгөгдсөн бодит тоон дарааллын арифметик дунджийг ол.
Input
Эхний мөрөнд бодит тоон дарааллын элементийн тоо n өгөгдөнө. n<=10,000.
Дараагийн мөрөнд n ширхэг тоо зайгаар тусгаарлагдан өгөгдөнө.
Output
Арифметик дунджийг таслалаас хойш 2 оронгийн нарийвчлалтайгаар хэвлэнэ.
Example
Input:
3
4.2 5.3 6.24
Output:
5.25
| Нэмсэн: | Bataa |
| Огноо: | 2013-01-23 |
| Хугацааны хязгаарлалт: | 1s |
| Эх кодын хэмжээний хязгаарлалт: | 50000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Програмчлалын хэлүүд: | ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE |
| Эх сурвалж: | Б.Отгонбаяр |
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2024-05-17 06:21:43
#include<stdio.h> int main() { int n; scanf("%d",&n); double a[n],sum = 0; for(int i = 0; i < n; i++) { scanf("%lf",&a[i]); sum += a[i]; } sum/=n; printf("%.2f",sum); return 0; } berh sama oonh |
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2024-05-16 05:28:08
yioohhhhhhahahah |
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2024-04-27 08:28:52
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⡛⠉⢯⣒⢤⡀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⡖⢡⡐⡄⢀⡀⠈⢙⢮⡳⡄⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡠⠣⠀⠂⠀⠈⠀⠀⠈⣈⠷⢉⠃⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡰⠋⡐⡀⠀⠀⠀⠀⠀⣐⠼⢁⡞⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⠣⢁⠐⠈⠆⣀⡈⠀⠲⢃⢠⠎⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠐⠂⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⣰⡅⠂⠄⠂⠈⠐⢠⠓⢢⠱⣨⠃⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⣴⠤⣤⢤⣤⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠏⣿⠗⠀⠀⠀⠀⠂⠈⠀⠈⠄⣼⠁⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⣾⡟⣬⠛⣭⢫⡍⣶⢳⣦⡄⠀⠀⠀⠀⠀⠀⠀⠀⡪⠡⡞⠂⠀⠀⠀⠀⢢⠀⠀⠀⠀⣾⠃⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⣾⡓⠤⠁⠎⠱⡈⡜⢥⢻⣹⢻⠷⡶⣶⡶⢶⣶⣾⡵⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠐⠠⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⣼⡧⠙⢢⠁⡈⠀⠀⠈⠀⠁⠋⠄⢊⠑⠄⠘⡀⢎⡝⡿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠐⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⢀⣾⡿⢤⡁⢂⠡⠀⠀⠀⠀⠀⠀⡈⠁⢁⠊⠴⠓⠁⡜⣾⠇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⢀⣴⣿⢟⡽⣂⠖⡄⢂⢀⣴⠼⡞⡿⣛⡝⠛⠛⠾⣦⣤⣾⡝⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⠂⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⢠⣾⣏⠳⢎⣖⠹⣎⡜⣧⡿⠡⢎⠱⠑⠨⠈⠁⠀⠀⠈⠉⣻⡄⠐⡀⠀⠀⠀⠀⠀⠀⠀⠀⢐⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⢸⡗⡮⣙⠦⡸⡙⣼⡿⢋⠀⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⡟⠠⠐⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⢸⣇⡳⡵⣊⠕⣩⡟⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡾⠁⠁⠀⠀⠀⠀⠀⠀⠀⠀⢀⠀⣲⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⢸⣿⣟⣡⢦⣽⡟⠐⠁⠀⢀⠠⠀⠀⠀⠀⠀⠀⠀⠀⢠⡇⠘⠀⠀⠀⠀⠀⠀⠀⠀⠀⣸⢸⠃⣀⣀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⢸⡿⠏⡉⣤⣿⠡⢈⠤⢁⠂⠀⠀⠀⠀⠀⠀⠀⠀⠀⣞⢡⠀⢀⠀⠀⠀⠀⠀⠀⠀⣴⢋⣿⠾⠃⠒⠘⠳⣶⣄⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⢠⣞⣵⠶⣿⣿⢁⡞⠤⠒⠠⠁⠂⠀⠀⠀⠀⠀⠀⠀⢰⡏⢆⠂⠄⠀⠀⠀⠀⠀⠀⠩⢄⣿⠋⠁⠀⠀⠁⠁⠡⡘⣿⠀⠀⠀⠀⠀⠀ ⠀⣰⣿⡟⢡⣾⢿⣌⠳⡘⠤⠉⠄⠀⠀⠀⠀⠀⠀⠀⠀⠀⡾⡑⠌⡐⠈⠄⠀⠂⢁⠐⢌⢂⣿⢃⠉⠀⠀⠠⢈⠠⡑⢆⢽⠀⠀⠀⠀⠀⠀ ⢀⣿⡟⢡⣿⡟⢮⢌⢣⠐⠄⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⣰⢏⠱⠈⠄⠡⠀⠌⡐⢀⠋⢤⣫⠇⠂⠀⠀⠀⠁⡀⠤⠱⣈⡟⠀⠀⠀⠀⠀⠀ ⢸⣿⣇⣳⡯⡝⢮⡘⢄⠃⠌⠀⠀⠀⠀⠀⠀⠀⠀⢀⣼⠏⡌⠢⠁⠌⠠⢁⠂⠔⡈⠜⣲⠏⠀⠀⠀⠀⠠⠁⢀⢀⠂⣵⡷⠤⢤⡤⣀⠀⠀ ⢸⣿⣟⡶⡹⣍⠦⡑⡈⠄⠀⠀⠀⠀⠀⠀⠀⠀⠤⣹⠣⡘⠠⠁⠌⠀⡁⢂⠌⡠⢉⣼⠇⠀⠀⠀⠀⠀⠂⢈⠀⡠⠘⣴⠏⠈⠀⠈⠺⢵⡆ ⢸⣿⣿⢶⡹⢆⠳⠄⡁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠐⠠⠁⠄⡁⠌⠀⠐⠄⠊⠤⡁⢧⡾⠁⠀⠀⠀⠀⠀⠀⠄⠐⠠⢹⡏⠀⠀⡀⠄⡑⢠⡇ ⠸⣿⣿⣏⡳⢍⡚⢀⠀⠀⠀⠀⠀⠀⠀⡀⠀⠀⢀⠂⣁⠂⠀⠀⠀⠌⡐⢉⠐⡌⢺⡇⠀⠀⠀⠀⠀⠀⠀⠀⠊⢰⡟⠀⠀⠀⠀⢂⠐⢯⡜ ⠀⢻⣿⣯⣗⡪⢐⠂⠄⡀⠀⠀⢀⠀⠄⡀⠠⠐⠠⡈⠄⠌⡐⠀⠐⠠⠈⠄⢂⠜⣹⠄⠀⠐⠀⠀⣀⠁⢂⠐⢠⡿⠀⠀⠀⠀⡀⠌⡈⠵⡇ ⠀⢸⣿⣿⣿⣷⡠⢌⡐⢀⠁⠄⠂⠌⡀⠀⠀⠄⠡⢐⠨⠐⠀⡐⠈⠄⠡⢈⠆⡹⢜⡀⠂⠀⠀⡐⠠⠈⢃⠀⣾⠀⠀⠀⠀⠀⠠⢀⠓⡸⡇ ⠀⠈⣿⣿⣿⣿⣿⣶⣌⣦⡘⡬⣑⢢⠐⡀⠂⠌⡠⠁⠂⠁⠄⠄⠁⠌⡐⢂⠬⡑⢆⠀⠠⢀⠂⠡⢀⠂⠌⣸⠧⠀⠀⠀⠠⢀⠁⢢⠘⣼⠁ ⠀⠀⢿⣿⣿⣿⣿⣿⣿⡼⣧⢧⣣⠜⣄⠣⡘⠤⡠⠀⠀⠘⡀⠀⠄⣀⢃⡘⢤⠛⠄⠘⠠⢄⠃⠤⠀⠄⡀⣿⠀⠀⠀⠠⠀⠀⡘⠄⣻⢻⠀ ⠀⠀⢸⣿⣿⣿⣿⣿⣿⣿⣯⣿⣳⢿⣤⡓⡜⡐⠀⠀⡄⢃⠄⠠⡀⢄⠢⢜⢢⡉⡐⢈⠐⡈⡘⠤⢉⡐⢡⠏⡐⠠⠁⠂⡀⠡⢐⢨⢴⠏⠀ ⠀⠀⠀⢿⣿⣿⣿⣿⣿⣿⣿⣷⣯⣟⣿⣽⣳⣍⢶⣱⣌⠂⠌⢁⠰⣈⠲⣍⠢⡐⠁⠀⠀⠐⠀⢀⠂⢄⠣⡘⠠⢁⠂⡐⠠⢁⢢⢎⡿⠀⠀ ⠀⠀⠀⠈⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣾⣿⣿⣿⣿⣿⣾⣿⣶⣮⣶⣼⢳⣎⡱⢌⠢⡁⠄⣁⠀⠂⢌⠂⢆⠁⠂⠄⡂⠥⢑⡈⢲⡾⠃⠀⠀ ⠀⠀⠀⠀⠈⢻⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣷⣿⣿⣾⣵⣯⣶⣝⡲⢌⡘⢡⠂⢍⠠⠌⡐⠠⠘⡄⢣⢼⡿⠁⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠉⠻⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣯⣿⣽⣶⣭⢦⣉⠦⡘⢄⠢⣑⢣⡜⣱⠞⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠙⠿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣽⣯⣷⣻⢯⣟⣿⣿⣷⣟⣾⣵⣮⣵⣺⣦⠿⠃⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠛⠿⠿⠿⠿⠿⠿⠿⠿⠛⠋⠙⠛⠛⠛⠻⠿⠿⠿⣿⣿⣿⣿⡿⠟⠛⠉⠀⠀⠀⠀⠀⠀⠀⠀ |
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2024-01-16 10:30:09
ene c++ deer bodsn bagiid helhd bro makes you shuu hu zgr nuhursug zuvlguu lalraa |
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2024-01-05 17:00:11
import java.util.Scanner; public class Think { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); double[] b = new double[n]; double result = 0; double r = 1; int i = 0; while (i < n) { b[i] = in.nextDouble(); result = result + b[i]; i++; } r = result / n; System.out.printf("%.2f", r); } } |
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2022-12-16 02:13:15
#include<bits/stdc++.h> #include<cmath> using namespace std; double p,s=0,a[10000]; long long i,n; main(){ scanf("%lld",&n); for(i=1;i<=n;i++) scanf("%lf",&a[i]); for(i=1;i<=n;i++) { s=s+a[i]; } p=s/n; printf("%.2lf",p); } huultsgaa suguudaa |
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2022-11-08 05:14:43
#include<bits/stdc++.h> using namespace std; long a[10001]; main(){ int n, i; double avg, s=0; cin >> n; for (i=0; i<n; i++){ cin >> a[i]; } for (i=0; i<n; i++) { s = s + a[i]; } avg = s / n; printf("%.2lf", avg); } |
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2022-09-22 12:36:26
boolean f=true; double nu1=0; double a=0,b=0; while(f) { System.out.print(""); nu1 =scan.nextDouble(); if(nu1<10000) break; } double arr[]=new double[10]; for(int i=0;i<=(nu1-1);i++) { System.out.print(""); double nu2=scan.nextDouble(); arr[i]=nu2; a+=arr[i]; b++;} System.out.printf("%.2f",(a/b)); |
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2022-05-27 06:23:29
#include<cstdio> #include<math.h> int main(){ //freopen("17.in","r",stdin); //freopen("17.out","w",stdout); int a,b,c,d,e,f; scanf("%d",&a); d=1; if(a%2==0) { for(c=2;c<=a;c=c+2) { d=d*c; } } else { for(c=1;c<=a;c=c+2) { d=d*c; } } printf("%d",d); return 0; } |
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2022-03-18 16:20:32
Practice make you Stronger ---------------------------- #include <iostream> #include <math.h> using namespace std; int main(){ int a; cin >> a; double b[a-1] , all=0; for(int i=0; i<a; i++){ cin >> b[i]; all += b[i]; } cout.setf(ios::fixed); cout.precision(2); cout << all/a << endl; } |
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