SPOJ.com - Problem RGB7310

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RGB7310 - Хоёрын зэрэгт

Өгөгдсөн тоо хоёрын зэрэгт мөн бол YES үгүй бол NO гэж хэвлэ.

Input

Бүхэл тоо өгөгдөнө.

Output

2-ын зэрэгт бол YES үгүй бол NO.

Example

Input:
16

Output:
YES

Submit solution!

Нэмсэн:	Bataa
Огноо:	2013-01-11
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2021-12-18 17:08:45
#include<stdio.h>

main()
{
double a=1,s=1,k=1,d;
scanf("%lf",&d);
if(d>0)
{
while(a)
{
if(d==1)
{
printf("YES");
a=0;
}
s=s*2;
k=k/2;
if(s>=d || k>=d)
{
if(s==d)
{
printf("YES");
a=0;
}
else if(k==d)
{
printf("YES");
a=0;
}
else
{
printf("NO");
a=0;
}
}
}
}
else
printf("NO");
}
Yu buruu bn

2021-11-18 22:57:33
int a=2;
Scanner sc=new Scanner(System.in);
a=sc.nextInt();
while(a>=2 & a%2==0) {
a=a/2;
}
if(a==1 ) {
System.out.print("YES");

}
else System.out.print("NO");

2021-10-30 07:27:07
#include<iostream>
#include<cmath>
using namespace std;
int main(){
int a,i;
cin>>a;
i=0;
while(pow(2,i)<=a){
i=i+1;
}
if(pow(2,i-1)==a)
cout<<"YES";
else
cout<<"NO";
return 0;
}

2021-10-28 19:16:37
2iin zeregt bish zvgeer toonii zeregt shvv

2021-07-20 11:47:15
#include <iostream>
using namespace std;

int main()
{
int n, a=0, i=0, s=0, x ;
cin>>n;

while(n>a)
{
i++;
s=i*i;
a++;

if(n==s)
x=s;
}
if(n==x)
{
cout<< "YES";
}
else cout<<"NO";
}

2021-04-21 08:52:44
#include <stdio.h>

bool check(int n)
{
while (n>1)
{
if (n%2!=0)
{return false;
break;
}
n=n/2;
}
return true;
}

main ()
{
int n, b, a=0;
scanf("%d",&n);

if(check(n))
printf("YES");
else
printf("NO");
}

2021-04-21 08:38:57
copy dis shit
#include <bits/stdc++.h>
using namespace std;
int main (){
int n;
cin>>n;
while (n>=2 && n%2==0){
n=n/2;
}
if (n==1){
cout<<"YES"<<endl;
}
else
cout<<"NO"<<endl;

return 0;
}

2021-03-22 01:31:37
#include <stdio.h>

int main(void) {
int n,i;
scanf("%d",&n);
for(;n%2==0;n/=2)
i=n/2;
if(i==1)
printf("YES");
else
printf("NO");
} ene shalgagch buruu beno

2020-11-06 02:15:57
#include <bits/stdc++.h>
using namespace std;
int main (){
int a;
cin>>a;
while (a>=2 && a%2==0){
a=a/2;
}
if (a==1){
cout<<"YES"<<endl;
}
else cout<<"NO"<<endl;
return 0;
}

2020-07-30 04:47:51
//right code
#include <bits/stdc++.h>
using namespace std;
int main (){
int a;
cin>>a;
while (a>=2 && a%2==0){
a=a/2;
}
if (a==1){
cout<<"YES"<<endl;
}
else cout<<"NO"<<endl;
return 0;
}

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7310 - Хоёрын зэрэгт

Input

Output

Example