SPOJ.com - Problem RGB7311

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RGB7311 - Гуравын зэрэгтэд хураа

Өгөгдсөн тоог 3-ын зэрэгтэд хураа.

Input

Бүхэл тоо өгөгдөнө.

Output

Хураагдсан тоо.

Example

Input:

36 Output:

4

Submit solution!

Нэмсэн:	Bataa
Огноо:	2013-01-11
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

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2020-11-19 08:25:46
#include<stdio.h>
int main(){
int a;
scanf("%d",&a);
while (a%3==0){
a=a/3;
}
printf("%d", a);
return 0;
}

2020-11-06 02:17:34
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int n;
scanf("%d",&n);
while(n%3==0)
{
n=n/3;
}
printf("%d",n);
}

2020-11-06 02:17:33
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int n;
scanf("%d",&n);
while(n%3==0)
{
n=n/3;
}
printf("%d",n);
}

2020-07-04 06:54:43

2019-12-17 12:45:21
#include<iostream>
using namespace std;
int a,n,m,s=0;
int main()
{
cin>>a;
while(a%3==0)
{
a=a/3;
}
cout<<a;
}

2019-12-10 08:29:18
lol it's so esey

2019-12-03 07:52:39
iim amarhan bodlogo haana bsiin

2019-10-31 06:46:15
uil

2019-10-29 08:44:13
#include <iostream>

using namespace std;

int main(){
int n;
cin>>n;
while(n%3==0){
n=n/3;
}
cout<<n<<endl;
return 0;
}mo huul

2019-10-12 06:05:44
hahahahahahahahahahahahahahahahahahahahahahahahahahahahahaha
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Last edit: 2019-10-12 06:06:33

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7311 - Гуравын зэрэгтэд хураа

Input

Output

Example

Input:

36

Output:

4