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RGB7402 - Давхар давталт 2

Өгөгдсөн бүхэл тоон тусламжтайгаар дараах тоон хэлбэрийг үүсгэ.

Input

Бүхэл тоо өгөгдөнө. 10-аас бага.

Output

Өгөгдсөн тоог ашиглан жишээн дээрх тоон хэлбэрийг үүсгэ.

Example

Input:
5
Output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5

Нэмсэн:Bataa
Огноо:2013-01-14
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2024-04-10 12:51:53
hii
2024-01-24 15:45:41
suddenly im gettin dumb asf
2024-01-21 10:15:46
#include <stdio.h>
int n,i,j;
int main()
{
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
printf(" %d",j);
printf("\n");
}
return 0;
}
2023-12-08 04:56:09
enig oilgohgu baival zueree bi c gsn oilgohgu bn hamtdaa huultsgaaay homies
2023-09-14 10:01:49
Munkh-Orgil muu sda
2023-07-12 15:00:56
#include <iostream>
using namespace std;
int main(){
int n,i,j;
cin>>n;
for(i=1;i<=n;i++){
for(j=1;j<=i;j++){
cout<<j<<" ";
}
cout<<endl;
cout<<endl;
}
return 0;
}
2023-04-16 05:01:39
#include <iostream>
using namespace std;
int main (){
int n;
cin >> n;
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= i; j++){
cout << j << " ";

}
cout << endl;
}
} huul2
2023-04-09 05:07:53
enig oilgohgu baival zueree bi c gsn oilgohgu bn hamtdaa huultsgaaay homies
2023-04-09 05:07:49
enig oilgohgu baival zueree bi c gsn oilgohgu bn hamtdaa huultsgaaay homies
2023-02-15 17:19:39
hinoru bna




#include<bits/stdc++.h>
using namespace std;
int main()
{
long long int n,j;
cin>>n;
for(int i=1;i<=n;i++)
{
for( j=1;j<=i;j++)

cout<<j<<" ";
cout<<"\n";
}
return 0;

}
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