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RGB7404 - Давхар давталт 4

Өгөгдсөн тоон тусламжтайгаар жишээн дээрхтэй төстэй тоон хэлбэрийг үүсгэ.

Input

Бүхэл тоо өгөгдөнө.

Output

Жишээн дээрхтэй төстэй тоон хэлбэрийг үүсгэ.

Example

Input:
5
Output:
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1

Нэмсэн:Bataa
Огноо:2013-01-14
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2022-11-16 06:06:27
suvdaa chi arhi chin ym uu
2022-11-16 05:53:09
BITGII HUUL








2022-11-16 05:52:37
BITGII HUUL








2022-10-19 16:57:04
yag yagaad hasaad hasaad 5 garaad bgag n tailbarlaad ogoh hun bnu pls
2022-04-26 08:50:59
include<iostream>
using namespace std;
main (){
int a;
cin a;
for(i=1; i<=a; i++){
for(j=a; j>0; j--){
cout << j;
}
}
}

Ananda
2022-01-08 13:00:58
#include<stdio.h>
int main()

{
int a,b,c;
scanf("%d",&a);
for(b=a ; b>=1; b--){
for(c=a; c>=b ; c--)
printf("%d ",c);
printf("\n");

}
}
pls copy this lol
2020-09-16 11:28:48
#include <iostream>
using namespace std;

int main() {
int j,i,n;
cin>>n;
for(i=n; i>=1; i--)
{
for(j=n; j>=i; j--)
cout<<j<<" ";
cout<<endl;
}
return 0;
}
2019-10-19 07:25:45
#include <cstdio>

int main () {
int n;
scanf("%d", &n);
for(int i = n ; i >= 1 ; i--){
for(int j = n ; j >= i ; j--){
printf("%d ", j );
}
printf("\n");
}
}
2019-04-05 06:20:31
nmg jack gdg bi bol uneheer tng boyyy
2019-03-18 11:55:57
#include<stdio.h>
#include<math.h>
main(){
int a, b, n, d;

scanf("%d", &n);

for(int i=n;i>=1;i--){

for(int j=n;j>=i;j--){

printf("%d ", j);
}
printf("\n");
}
}
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