QTREE2 - Query on a tree II

You are given a tree (an undirected acyclic connected graph) with N nodes, and edges numbered 1, 2, 3 ...N-1. Each edge has an integer value assigned to it, representing its length.

We will ask you to perform some instructions of the following form:

  • DIST a b : ask for the distance between node a and node b
    or
  • KTH a b k : ask for the k-th node on the path from node a to node b

Example:
N = 6
1 2 1 // edge connects node 1 and node 2 has cost 1
2 4 1
2 5 2
1 3 1
3 6 2

Path from node 4 to node 6 is 4 → 2 → 1 → 3 → 6
DIST 4 6 : answer is 5 (1 + 1 + 1 + 2 = 5)
KTH 4 6 4 : answer is 3 (the 4-th node on the path from node 4 to node 6 is 3)

Input

The first line of input contains an integer t, the number of test cases (t <= 25). t test cases follow.

For each test case:

  • In the first line there is an integer N (N <= 10000)
  • In the next N-1 lines, the i-th line describes the i-th edge: a line with three integers a b c denotes an edge between a, b of cost c (c <= 100000)
  • The next lines contain instructions "DIST a b" or "KTH a b k"
  • The end of each test case is signified by the string "DONE".

There is one blank line between successive tests.

Output

For each "DIST" or "KTH" operation, write one integer representing its result.

Print one blank line after each test.

Example

Input:
1

6
1 2 1
2 4 1
2 5 2
1 3 1
3 6 2
DIST 4 6
KTH 4 6 4
DONE

Output:
5
3

Added by:Thanh-Vy Hua
Date:2006-08-27
Time limit:1s
Source limit:15000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ERL JS-RHINO NODEJS PERL6 VB.NET
Resource:Special thanks to Ivan Krasilnikov for his alternative solution

hide comments
2017-06-23 20:53:06
For the KTH query, will O(k) complexity pass? Or something else is required?

Edit: O(logN + k) is sufficient.

Last edit: 2017-06-23 21:43:03
2017-05-25 17:26:38
AC after 4 WA. Feel good. I used RMQ on Level eulerian walk to get LCA and binary search on levels to get kth Ancestor
2017-03-02 00:06:42
This is way easier than QTREE; you don't need HLD, only LCA. You also DO NOT need long long; which you could infer from the input restrictions btw.
2016-10-29 21:07:15 Ashwani Gautam
can use hld, use long long int for anything related to summation of edges
2016-08-28 21:03:27
easy . sparse Matrix approach for LCA calculation.
2016-07-26 19:51:48
easy ;) confidence booster
2016-05-15 09:32:36
getting tle may be bcoz of method of finding ancestors ...plz help
2016-04-03 03:22:29
Get Wa and Don't know why.
2016-03-26 14:13:56 Abhinandan Agarwal
@chandan Mittal- No, I checked it.

Last edit: 2016-03-26 14:35:26
2015-10-22 11:03:20
I was using doubling algorithm to get lca.
This problem is very easy.
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