SEQ - Recursive Sequence

Sequence (ai) of natural numbers is defined as follows:

   ai = bi (for i <= k)
   ai = c1ai-1 + c2ai-2 + ... + ckai-k (for i > k)

where bj and cj are given natural numbers for 1<=j<=k. Your task is to compute an for given n and output it modulo 109.

Input

On the first row there is the number C of test cases (equal to about 1000).
Each test contains four lines:

k - number of elements of (c) and (b) (1 <= k <= 10)
b1,...,bk - k natural numbers where 0 <= bj <= 109 separated by spaces
c1,...,ck - k natural numbers where 0 <= cj <= 109 separated by spaces
n - natural number (1 <= n <= 109)

Output

Exactly C lines, one for each test case: an modulo 109

Example

Input:
3 
3 
5 8 2 
32 54 6 
2 
3 
1 2 3 
4 5 6 
6 
3 
24 354 6 
56 57 465 
98765432

Output:
8 
714 
257599514

Added by:Paweł Dobrzycki
Date:2005-04-29
Time limit:0.5s-3s
Source limit:8196B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:IV Podlasian Contest in Team Programming

hide comments
2017-12-26 16:41:57
when to take mod
2017-08-30 20:26:50
ac in 1 go
2017-08-22 19:43:16
How can output of 3rd case be 257599514, this number is greater than 1e9 and so by modulo the output must be 57599514. Where am I going please help..
2016-08-06 13:56:12 Rajat Sharma
Java: will learn matrix exponentiation with recursion, linear recursive equations, how to solve these equations by converting the addition into multiplicative expressions i.e. through matrices.
2016-03-07 15:56:45 Deepak Singh Tomar
matrix_exponentiation. Thanks fushar :)
2016-02-03 17:26:12 minhthai
be careful the mod is 10^9 not 10^9 + 7 :)
2015-08-27 18:45:42 Ðức Tân
dễ vãi
2015-06-25 07:28:24
Hint: While doing matrix multiplication, DON'T do temp[][] += mod(F[][] * M[][]);
instead do temp[][] = mod(temp[][] + F[][] * M[][])
costed me 3 WA's ... phew... best of luck
2015-06-21 18:23:23 sHaShAnK sHeKhAr
Nice problem to reach 150 :)
2015-05-30 15:59:01 i_am_looser
learnt something new.......... ; )
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