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HO1040 - Нийлбэрийн хагас

Өгсөн хоёр бүхэл тооны нийлбэрийн хагасыг ол.

Input

Тус бүр 10^9 -с хэтрэхгүй хоёр бүхэл тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

Үр дүнг таслалаас хойш нэг орны нарийвчлалтай хэвлэ.

Example

Input:
4 5

Output:
4.5
Submit solution!
Нэмсэн:munkhbat
Огноо:2013-01-13
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:Бүгд дараах хэлүүдээс бусад: ASM64 NCSHARP JULIA PYPY3
hide comments
2023-10-23 07:55:05
amjilt cyber surgulin 7-1 angin gomo tengis saraanad sn
2023-04-25 10:32:38
#include<bits/stdc++.h>
using namespace std;
int main()
{
double a,b,c=0;
cin >> a >> b;
c=(a+b)/2;
printf("%.1f",c);
}
//easy shdee bro
2023-04-10 08:08:47
#include<bits/stdc++.h>
using namespace std;
int main()
{
double a, c, b;
scanf("%lf%lf" ,&a ,&b);
printf("%.1lf" ,(a+b)/2);
} bayrlaj yv
2023-03-16 05:42:21
#include<bits/stdc++.h>
using namespace std;
int main()
{
double a, c, b;
scanf("%lf%lf" ,&a ,&b);
printf("%.1lf" ,(a+b)/2);
} munji
2022-11-03 06:46:46
#include<bits/stdc++.h> //6.5
using namespace std;
int main (){
double a,b,d,e;
cin>>a>>b;
d=(a+b)/2;
printf("%.1lf",d);
}
2022-10-31 02:19:40
⠀⠀⠀⠀⠀⣀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿⣿⣆⣀⣀⠀⣿⠂⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⠻⣿⣿⣿⠅⠛⠋⠈⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠘⢼⣿⣿⣿⣃⠠⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣟⡿⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣠⣴⣾⡆⠸⣿⣿⣿⡷⠂⠨⣿⣿⣿⣿⣶⣦⣤⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣤⣾⣿⣿⣿⣿⡇⢀⣿⡿⠋⠁⢀⡶⠪⣉⢸⣿⣿⣿⣿⣿⣇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣄⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠃⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢹⣿⣵⣾⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣯⡁⠀⠀⠀⠀⠀

2022-09-20 07:25:25


Last edit: 2022-09-26 06:49:43
2022-09-20 07:21:23


Last edit: 2022-09-26 06:49:47
2022-09-20 06:56:33


Last edit: 2022-09-26 06:49:53
2022-03-24 12:01:03
#include <iostream>

using namespace std;

int main() {
int q,w,e,r;
cin>>q>>w;
e=(q+w)/2;
r=(q+w)%2;
cout<<e<<endl<<r;
return 0;
}
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