SPOJ.com - Problem RGB7002

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RGB7002 - Гурвалжин

Өгөгдсөн гурвалжны периметрийг ол.

Input

Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Гурвалжны периметр.

Example

Input:
3 4 5

Output:
12

Submit solution!

Нэмсэн:	Bataa
Огноо:	2011-01-15
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2023-01-07 07:16:04
#include<bits/stdc++.h>

using namespace std;

int main () {
//freopen ("input.txt","r",stdin);
//freopen ("output.txt","w",stdout);
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long n, m, t, i, r, X, Y, x, j,z, y, s, ans, p;

//cin >> t;
cin >> n >> m;
long long Sum[1002][1002] = {0};
ans = 0;

for ( i = 1; i <= n; i ++) {
for ( j = 1; j <= m; j++) {
cin >> x;
Sum[i][j] = Sum[i - 1][j] + Sum[i][j - 1] - Sum[i - 1][j - 1];
Sum[i][j] += x;
}
}
cin >> t;
while ( t --) {
cin >> x >>y >> X >> Y;
s = Sum[X][Y] - Sum[x - 1][Y] - Sum[X][y - 1] + Sum[x - 1][y - 1];
cout << s << "\n";
}
}

2022-12-24 16:02:12
#include <iostream>
using namespace std;

int main(){
int a,b,c;
cin >> a >> b >> c;
cout << a + b + c;
} Huul2

2022-12-09 07:23:26
#include<stdio.h>
int main(){
int n,a,b;
scanf("%d",&n);
a=100;
b=a*n;
printf("%d",b);
return 0;
}

2022-12-07 03:34:28
#include<iostream>
using namespace std;
int main(){
int a,b,c,d,e;
cin>>a>>b;
c=(a*b)/2;
cout<<c<<endl;

}

2022-12-07 03:32:51
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,d,i;
cin>>a>>b>>c>>d;
if((a+b)%2==(c+d)%2) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}

2022-12-07 03:32:18
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,d;
scanf("%d%d%d%d",&a, &b, &c, &d);
if ((a+b)%2==0 ^ (c+d)%2!=0) printf("YES");
else printf("NO");
}

2022-12-07 03:31:16
#include<iostream>
using namespace std;
int main(){
int a,b,c,d,e;
cin>>a>>b;
c=(a*b)/2;
cout<<c<<endl;

}

2022-12-07 03:30:16
#include<bits/stdc++.h>
using namespace std;
int main (){
long a,b,c,d;
scanf("%d%d%d%d",&a, &b, &c, &d);
if ((a+b)%2==0 ^ (c+d)%2!=0) printf("YES");
else printf("NO");
}

2022-12-07 03:28:53
#include<bits/stdc++.h>
using namespace std;
int main (){
int r1,s,r2;
cin>>r1>>s;
r2=(s*2)-r1;
cout<<r2<<endl;
}

2022-12-07 03:22:45
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,d;
cin>>a>>b;
c=2*b-a;
cout<<c<<endl;
}

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7002 - Гурвалжин

Input

Output

Example