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RGB7002 - Гурвалжин

Өгөгдсөн гурвалжны периметрийг ол.

Input

Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Гурвалжны периметр.

Example

Input:
3 4 5

Output:
12


Нэмсэн:Bataa
Огноо:2011-01-15
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2022-11-04 07:24:23
#include <iostream>

using namespace std;

int main() {
int a ,b;
cin >> a >> b;
for ( int i = 1; i <= a; i++ ) {
if ( i % 2 == 1 ) {
for ( int i = 1; i <= b; i++ ) {
cout << "#";
}
}
else {
if ( i % 4 == 0 ) {
cout << "#";
b--;
for ( int i = 1; i <= b; i++ ) {
cout << ".";
}
b++;
}
else {
b--;
for ( int i = 1; i <= b; i++ ) {
cout << ".";
}
cout << "#";
b++;
}
}
cout << endl;
}
return 0;
}
2022-11-01 06:02:36
https://youtu.be/dQw4w9WgXcQ
2022-10-31 15:13:23
int a, b, c, p;
cin>>a>>b>>c;
p=a+b+c;
cout<<p<<endl;
2022-10-27 08:45:08
E
2022-10-27 02:33:08
#include<bits/stdc++.h>
using namespace std;
int main() {
int a, b, c, p;
cin>>a>>b>>c;
p=a*b*c;
cout<<p<<endl;
return 0;
}
2022-10-25 10:35:18
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,s,c;
scanf("%d%d%d",&a,&b,&c);
s = a+b+c;
printf("%d\n",s);
}
2022-10-17 03:22:56
so ez
2022-10-03 03:27:37
int main() {
int a, b, c, p;
cin>>a>>b>>c;
p=a+b+c;
cout<<p<<endl;

return 0;
}nice bro
2022-09-12 09:58:22
https://play.typeracer.com?rt=2i6fudm85h
2022-09-12 09:58:17
https://play.typeracer.com?rt=2hk59qvwl2
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