LASTDIG - The last digit

Nestor was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives him two numbers a and b. The problem consist of finding the last digit of the potency of base a and index b. Help Nestor with his problem. You are given two integer numbers: the base a (0 ≤ a ≤ 20) and the index b (0 ≤ b ≤ 2,147,483,000), a and b both are not 0. You have to find the last digit of ab.

Input

The first line of input contains an integer t, the number of test cases (t ≤ 30). t test cases follow. For each test case will appear a and b separated by space.

Output

For each test case output an integer per line representing the result.

Example

Input:
2
3 10
6 2

Output:
9
6

Added by:Jose Daniel Rodriguez Morales
Date:2008-12-01
Time limit:1s
Source limit:700B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: GOSU
Resource:Own

hide comments
2020-06-27 12:34:31
by using binary exponentiation answer is obtained in my system ide but online judge is claiming that its a wrong answer. Kindly anyone help me through it _/\_
2020-06-10 14:39:44
Turns out "a and b both are not 0" means that both are not simultaneously zero but can be individually zero
2020-06-09 08:48:34
700 Bytes how to resolve ?
2020-06-04 01:14:59
i cant find any mistake in my code pls hlp


Last edit: 2020-06-04 01:15:16
2020-05-30 05:45:25
stupid endl !!
2020-05-18 15:00:57
Here we only need to calculate (a^b)mod 10 with the help of modular exponentiation.

Last edit: 2020-05-18 15:05:57
2020-05-17 19:37:34
700B lol
2020-05-17 14:18:37
Euclid theorem gives cycle 4 for coprime numbers; others you can check, also with period 4.
2020-05-10 22:26:45
this little judge doesnt like pow function guys.Nothing is wrong with ur code people.
2020-05-08 12:15:31
easy problem
just use binary exponentiation or method of periodicity(as 2^1=1,2^2=4,2^3=8,2^4=16,2^5=32...)And this period goes on.
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