BYTESM2  Philosophers Stone
One of the secret chambers in Hogwarts is full of philosopher’s stones. The floor of the chamber is covered by h × w square tiles, where there are h rows of tiles from front (first row) to back (last row) and w columns of tiles from left to right. Each tile has 1 to 100 stones on it. Harry has to grab as many philosopher’s stones as possible, subject to the following restrictions:
 He starts by choosing any tile in the first row, and collects the philosopher’s stones on that tile. Then, he moves to a tile in the next row, collects the philosopher’s stones on the tile, and so on until he reaches the last row.
 When he moves from one tile to a tile in the next row, he can only move to the tile just below it or diagonally to the left or right.
Input
The first line consists of a single integer T, the number of test cases. In each of the test cases, the first line has two integers. The first integer h (1 <= h <= 100) is the number of rows of tiles on the floor. The second integer w (1 <= w <= 100) is the number of columns of tiles on the floor. Next, there are h lines of inputs. The ith line of these, specifies the number of philosopher’s stones in each tile of the ith row from the front. Each line has w integers, where each integer m (0 <= m <= 100) is the number of philosopher’s stones on that tile. The integers are separated by a space character.
Output
The output should consist of T lines, (1 <= T <= 100), one for each test case. Each line consists of a single integer, which is the maximum possible number of philosopher’s stones Harry can grab, in one single trip from the first row to the last row for the corresponding test case.
Example
Input: 1 6 5 3 1 7 4 2 2 1 3 1 1 1 2 2 1 8 2 2 1 5 3 2 1 4 4 4 5 2 7 5 1 Output: 32 //7+1+8+5+4+7=32
hide comments
ysk99:
20200304 10:14:53
test cases are so weak got accepted even without dp. 

gak:
20200229 14:36:37
TopDown DP worked like a charm. 

karandeep09:
20200201 11:43:49
AC in one go......... 

amar_shukla1:
20200128 15:47:14
this is ideal problem for a dp beginner 

zerodark:
20200121 12:01:06
If You are not able to Solve First solve sum in a triangle(sumtrian) on codechef. It's easy variant of this and then do this. 

sangmai:
20200119 08:14:17
I figure out the substructure only after reading the comments :(( 

makkycp:
20191226 11:30:20
C++ accepted.


hrittik16:
20191213 15:33:39
I think this a great beginners problem for learning dp 

sandeepd:
20191129 13:40:41
Nice problem for people starting out with DP. I would suggest that even if you solve the problem using memoization, do it also using bottomup approach. It will help you in realising solutions and solving other tougher DP problems. 

souvikd_pro:
20190919 19:29:23
memoization also worked !! 
Added by:  Paritosh Aggarwal 
Date:  20090221 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
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