BYTESM2  Philosophers Stone
One of the secret chambers in Hogwarts is full of philosopher’s stones. The floor of the chamber is covered by h × w square tiles, where there are h rows of tiles from front (first row) to back (last row) and w columns of tiles from left to right. Each tile has 1 to 100 stones on it. Harry has to grab as many philosopher’s stones as possible, subject to the following restrictions:
 He starts by choosing any tile in the first row, and collects the philosopher’s stones on that tile. Then, he moves to a tile in the next row, collects the philosopher’s stones on the tile, and so on until he reaches the last row.
 When he moves from one tile to a tile in the next row, he can only move to the tile just below it or diagonally to the left or right.
Input
The first line consists of a single integer T, the number of test cases. In each of the test cases, the first line has two integers. The first integer h (1 <= h <= 100) is the number of rows of tiles on the floor. The second integer w (1 <= w <= 100) is the number of columns of tiles on the floor. Next, there are h lines of inputs. The ith line of these, specifies the number of philosopher’s stones in each tile of the ith row from the front. Each line has w integers, where each integer m (0 <= m <= 100) is the number of philosopher’s stones on that tile. The integers are separated by a space character.
Output
The output should consist of T lines, (1 <= T <= 100), one for each test case. Each line consists of a single integer, which is the maximum possible number of philosopher’s stones Harry can grab, in one single trip from the first row to the last row for the corresponding test case.
Example
Input: 1 6 5 3 1 7 4 2 2 1 3 1 1 1 2 2 1 8 2 2 1 5 3 2 1 4 4 4 5 2 7 5 1 Output: 32 //7+1+8+5+4+7=32
hide comments
up79:
20161125 18:05:37
MY FIRST DP ! AC IN ONE GO :) 

vishalsingh:
20161101 06:43:46
BOTTOM UP approach


ani_geek9654:
20161025 14:36:46
BOTTOM UP


k_nushka:
20161011 09:12:49
Top down dp works too! :)


Harshwardhan Bansal:
20161001 15:21:18
Easy DP..Bottom Up approach...getting confidence..... :) 

spartax:
20160921 21:56:54
BufferedReader works fine !! 

shubham9466:
20160909 07:54:19
AC in 1 go!! simple:) 

kushalanand:
20160906 23:54:54
must practice for beginners like me.


lalywr:
20160903 08:20:13
that \n after every answer caused me a wa :( no recursion just memoisation ;D ad yeah , BOTTOM up Approach :) Last edit: 20160903 09:07:51 

Shravan Murali:
20160901 18:12:56
Recursive Top down approach kept giving me wrong answer , although bottom up worked :/ 
Added by:  Paritosh Aggarwal 
Date:  20090221 
Time limit:  0.141s0.393s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
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