EIGHTS  Triple Fat Ladies
Pattern Matchers have been designed for various sorts of patterns. Mr. HKP likes to observe patterns in numbers. After completing his extensive research on the squares of numbers, he has moved on to cubes. Now he wants to know all numbers whose cube ends in 888.
Given a number k, help Mr. HKP find the k^{th} number (indexed from 1) whose cube ends in 888.
Input
The first line of the input contains an integer t, the number of test cases. t test cases follow.
Each test case consists of a single line containing a single integer k (1 <= k <= 2000000000000).
Output
For each test case, output a single integer which denotes the k^{th} number whose cube ends in 888. The result will be less than 2^{63}.
Example
Input: 1 1 Output: 192
hide comments
g_o_d:
20171021 14:25:47
I suggest building the mathematical equation to find the trick !! 

moder_gabbar07:
20171010 14:49:34
First gets WA


hitesh87:
20170923 11:34:33
I would also say identify the pattern. 

prasanth292130:
20170830 18:33:00
AC in one go.........


nitisha1:
20170813 06:16:10
AC in 1st go..... 

amartya_k:
20170812 18:33:51
Hint: Try finding arithmetic difference from the sequence.


sai__teja_01:
20170803 15:16:38
AC in a go bro..! 

plidke:
20170727 14:01:10
There is a pattern :) Also very easy to see if You just print saveral such numbers. Last edit: 20170727 14:27:49 

cis_pie:
20170705 09:31:02
Haha at first go ... TLE and then observed the pattern. So AC in 2nd go! but the real fascinating thing is why you are able to see pattern.....? 

rinem13:
20170628 16:26:45
AC in One go !

Added by:  Matthew Reeder 
Date:  20061030 
Time limit:  1.197s 
Source limit:  30000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  AlKhawarizm 2006 