In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 <= T <= 1000). Then T lines follows. On each line you will find a integer number r (1 <= r <= 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

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	anon_007: 2019-06-23 09:00:01 use of setprecision is must costed me 4 WAs...
	aj_254: 2019-05-23 21:48:52 5 line code in python remember output format cose me one WA. very easy qusetion just need to diffretiate
	pandey101299: 2019-02-08 13:52:56 Easy one but use double for sum
	cypher33: 2019-01-04 17:17:34 Stupid Output format costed me 2 WA.... That was fair dinkum pain in the butt
	prabhav_123: 2019-01-02 22:36:09 \n costed me 1 WA, LOL!
	saket13: 2018-08-29 21:17:39 Be aware of the output format(Case 1: ans) Costed me two WAs..
	akjol2049: 2018-08-23 20:10:10 OMG...just (2*r)^2 and 0.25. Always the case:). As limit of angle between AB and diagonal approaches to 180.
	theabd123: 2018-06-01 07:29:21 Use double data type.....simple differentiation
	imkiller: 2018-05-30 20:37:07 5 lines Simple Maths Python3 :)
	sharmajatin741: 2018-05-15 09:12:38 Easy , AC in one go!