In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 <= T <= 1000). Then T lines follows. On each line you will find a integer number r (1 <= r <= 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

---

hide comments

< Previous 1 2 3 4 5 6 7 8 9 10 11 Next >
	rohan2802: 2017-01-15 22:07:59 Be careful of the output format.The 'C' in case is capital.Cost me 7 wa........
	aronzx: 2017-01-01 18:40:08 My 50th !
	kira28: 2016-12-14 22:30:41 AC by hook or crook...
	shantanu_sarin: 2016-12-14 14:31:07 mathematical concept required......
	asgupta_spoj: 2016-12-04 09:28:14 care of format of output required.
	E Naveen Kumar: 2016-11-09 11:57:02 REMEMBER ans should be in format "Case I: ans" It costed me 1 WA
	wompowe: 2016-10-31 08:55:27 when you add that "fixed number" to the value of computed number,it gives WA but when you just print it it gives AC. Don't know why
	roopansh: 2016-09-27 19:52:39 one WA for not printing "Case :".. took radius as double
	karan_batra: 2016-08-29 14:11:34 AC in one go :D. Comments do help. Take r as double.
	tni_mdixit: 2016-08-26 14:25:12 Case costed me 2 WA no diff needed just trigy :P no double or float needed