MICEMAZE  Mice and Maze
A set of laboratory mice is being trained to escape a maze. The maze is made up of cells, and each cell is connected to some other cells. However, there are obstacles in the passage between cells and therefore there is a time penalty to overcome the passage Also, some passages allow mice to go oneway, but not the other way round.
Suppose that all mice are now trained and, when placed in an arbitrary cell in the maze, take a path that leads them to the exit cell in minimum time.
We are going to conduct the following experiment: a mouse is placed in each cell of the maze and a countdown timer is started. When the timer stops we count the number of mice out of the maze.
Problem
Write a program that, given a description of the maze and the time limit, predicts the number of mice that will exit the maze. Assume that there are no bottlenecks is the maze, i.e. that all cells have room for an arbitrary number of mice.
Input
The maze cells are numbered $1, 2, \ldots, N$, where $N$ is the total number of cells. You can assume that $N \le 100$.
The first three input lines contain $N$, the number of cells in the maze, $E$, the number of the exit cell, and the starting value $T$ for the countdown timer (in some arbitrary time unit).
The fourth line contains the number $M$ of connections in the maze, and is followed by $M$ lines, each specifying a connection with three integer numbers: two cell numbers $a$ and $b$ (in the range $1, \ldots, N$) and the number of time units it takes to travel from $a$ to $b$.
Notice that each connection is oneway, i.e., the mice can't travel from $b$ to $a$ unless there is another line specifying that passage. Notice also that the time required to travel in each direction might be different.
Output
The output consists of a single line with the number of mice that reached the exit cell $E$ in at most $T$ time units.
Example
Input: 4 2 1 8 1 2 1 1 3 1 2 1 1 2 4 1 3 1 1 3 4 1 4 2 1 4 3 1 Output: 3
hide comments
ankit1cool:
20180617 21:28:39
Just reverse the edges and apply dijkstra's 

m2do:
20180513 10:56:09
The mouse is kept in the E cell as well. Hence answer will always be > 1. Use Dijkstra and FloydWarshall <3


ameyanator:
20180411 23:29:14
I think i too made a blunder mistake while solving it with dijkstra. Floyd Warshal is <3 

prestonbui97:
20180408 06:08:27
AC in one go !!!!!! 

ramini1996:
20180202 12:35:17
Just use Floyd Warshall algorithm !!! 

ayushtewary07:
20180201 19:58:36
AC in one go!!!


chetan4060:
20171212 10:29:48
dijkstra's rocks:) 

thanhbinh84:
20171207 03:11:01
Don't be fool by ideal sample TC. >_<


vishesh197:
20171104 13:25:38
you can do it in two ways first is do bfs from all vertices to exit cell adding the time(cost) and checking if time is less


rohit1507:
20170904 01:30:53
One can use anything... BFS,Dijkstra's, DFS.... as suitable! Just think simple. 
Added by:  overwise 
Date:  20071004 
Time limit:  0.310s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  ACM ICPC  SWERC 2001 