PRIME1 - Prime Generator


Peter wants to generate some prime numbers for his cryptosystem. Help him! Your task is to generate all prime numbers between two given numbers!

Input

The input begins with the number t of test cases in a single line (t<=10). In each of the next t lines there are two numbers m and n (1 <= m <= n <= 1000000000, n-m<=100000) separated by a space.

Output

For every test case print all prime numbers p such that m <= p <= n, one number per line, test cases separated by an empty line.

Example

Input:
2
1 10
3 5

Output:
2
3
5
7

3
5
Warning: large Input/Output data, be careful with certain languages (though most should be OK if the algorithm is well designed)

Information

After cluster change, please consider PRINT as a more challenging problem.

hide comments
shivam05_spoj: 2020-05-21 21:39:31

Can someone bring me any idea how to optimize the solution for the question as i have already done it in python3 but time limit exceeded.

md__talha__007: 2020-05-18 12:54:35

AC in one go!
Good question
Par sab farzi ka bhaukaal dikhate h "AC in one go"
likh kr to maine bhi dikha diya
Par maza nhi aaya

austino92: 2020-05-15 16:41:59

should i get all the inputs before processing?

dassatyaki: 2020-05-14 08:39:51

No need of sieve....run from 2 to square root and check if n is 1

summerbleach: 2020-05-12 11:22:06

The Osqrt(N) approach took 3.63 sec

sabat_raj3: 2020-05-10 21:50:56

Hey!no need for any complex logic. Use simple logic to traverse from m to n and then check from 2 to root(m) with two loops and it will be accepted. runtime o(nroot(n)).

subratdev: 2020-05-09 20:20:49

Since the range difference is 10^5,we need not create a historical array to save result from 1 - N (MAX - 10^9)
But creating a historical array of size 10^ 5 for every test case can be expensive.Any idea how to go ahead?

Last edit: 2020-05-09 20:21:39
prabhambrose: 2020-05-08 09:18:46

Use segmented Seive guyz ... its meant to be done that way

sarastic_19: 2020-05-05 21:32:42

I got tle error when i use sieveof eratosthenes

sachin954: 2020-04-30 09:14:13

you can use segmented sieve to solve this problem complexity of this is around max (root(n) , n-m)) * loglogn which is always less than o(n) for this problem

Idea is first generate all prime from 1 to root(n) and store that in a list and then check prime for number between range m to n using same like sieve


Added by:Adam Dzedzej
Date:2004-05-01
Time limit:6s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6