SPOJ.com - Problem RGB7002

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RGB7002 - Гурвалжин

Өгөгдсөн гурвалжны периметрийг ол.

Input

Гурвалжны талууд бүхэл тоогоор нэг мөрөнд зайгаар тусгаарлагдан өгөгдөнө.

Output

Гурвалжны периметр.

Example

Input:
3 4 5

Output:
12

Submit solution!

Нэмсэн:	Bataa
Огноо:	2011-01-15
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

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2024-01-08 07:43:08
⠀hariu harj baihaar tseku-g har⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣤⣤⣤⣄⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢠⣿⣿⣿⣿⣿⣿⣿⣦⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣰⣿⢹⡿⠟⠿⣿⣿⣿⣿⣷⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠠⣃⠇⡂⠄⢃⡐⢜⣻⣿⣿⣷⡆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠠⠤⠤⠀⢲⡂⠀⣀⣀⣀⠠⢄⠀⠀⢀⡡⠁⡜⡀⢆⠸⣮⣼⡄⠻⣿⣿⠇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣀⣀⡝⢠⠞⣇⡑⢢⠁⣆⣹⠈⣥⣼⡥⠛⠉⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⢀⢀⣴⣶⣾⣿⣿⣿⣿⣷⣥⢚⣽⡔⢡⣾⣶⣷⣾⣧⠋⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⢠⣿⣿⣿⣿⣿⣿⡄⠀⠀⠀⠈⠻⣞⣷⡥⣿⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⢸⣿⣿⣿⣿⣿⣿⣿⡀⠀⠀⠀⠀⠈⠛⠙⡅⢘⣾⢦⣤⠤⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⢼⣿⣿⣿⣿⣿⣿⣿⡇⠀⠀⠀⠀⠈⠀⠀⢇⡿⠹⡻⠼⠓⠅⠄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⢸⣿⣿⣿⣿⣿⣿⣿⠓⠀⠀⠀⠀⠀⠀⠈⣟⡳⢳⡓⢗⡚⣳⠆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠐⣾⣿⣿⣿⣿⣿⣿⡟⡄⠀⠀⠀⠀⠀⠀⡤⢄⠛⠋⠟⠩⢗⡠⢉⠗⠇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠐⣿⣿⡿⣿⣿⣿⣿⡏⠜⠀⠀⠀⠀⠀⠀⢇⢸⠇⠀⢠⠀⢠⢩⢣⡊⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⢸⢣⢓⡰⠠⢉⠙⠉⠄⠀⠀⠀⠀⠀⠀⠈⢆⠀⢰⡖⡐⣥⠓⡜⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⡈⢇⡎⡔⢡⠂⢸⡄⠀⠀⠀⠀⠀⠀⠀⠠⠈⢢⢳⣩⢞⡲⢭⠃⠀⢙⠀⠂⡈⠀⢑⠉⠀⢐⠠⠂⠀⠐⠄⠘⢢⠀⠀⠀⠠⠄⠀
⠨⢦⡄⡯⡔⡩⠄⡘⡜⡠⠀⠀⠀⠀⠀⠀⠀⠀⢈⢚⢺⡟⣮⠳⠁⠆⢀⡠⠀⡀⠀⠀⠀⠀⠀⠀⠤⣀⠀⠠⢄⡙⠶⡐⢂⠀⡀⠂⠀
⡠⠦⠤⣳⡜⡄⠂⠰⢡⠌⢄⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣟⠂⣁⠀⠘⠀⠇⠀⡀⠄⠁⠐⠀⠠⠐⠀⠃⠤⢂⡐⠗⠄⠀⠐⢄⠀⠀⠀
⠀⠀⠀⣵⡛⢶⡁⢀⢹⠑⡀⠐⠀⠀⠀⠀⠀⠀⠀⠀⠘⣘⠲⢀⡌⠠⢡⡄⠠⠁⠚⠀⡒⠐⡄⠀⢀⠀⢀⡀⠤⡷⠔⠀⢄⢂⣀⡀⠐
⠀⠀⠀⠸⡝⣮⢱⢊⠄⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡄⣠⠊⡁⠦⡁⠄⡎⢄⠈⡄⠡⠈⠁⠒⠨⡀⠀⢀⠀⠸⡀⠰⡈⡄⠃⣀⡔⣀
⠀⠀⠀⠀⠹⣎⣧⢋⠴⠘⣄⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢁⢕⡐⠂⢭⣼⢑⢌⢆⣴⡔⣠⢁⠂⠄⠜⡀⢆⠈⣾⡏⢀⡧⢄⣷⣿⠻⣿
⡤⣶⣶⣶⣶⣿⡼⢣⠎⡱⢬⠀⠀⠀⠀⠀⠀⠀⠀⠀⡀⣶⢥⠠⠁⠆⡐⠠⠼⣼⡿⢳⠁⠀⠀⠂⠀⡉⣸⣣⠚⡤⢘⣵⣿⣿⣿⠋⡈
⠈⠁⠉⠈⠀⠉⠈⠉⠉⠉⠉⠉⠉⠉⠉⠁⠐⠒⠒⠒⠒⠚⠒⠓⠚⠊⠙⠒⠒⠋⠠⢘⠀⠀⠜⠤⠵⠤⠤⠧⠤⠧⠋⡛⠛⠿⠋⠶⠇
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⠀⠀⠀⠐⠀⡀⠀⠀⠀⠀⠀⠈⢁⣱⡇⠀⠘⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠐⠐⠀⠀⠀⠀⠀⠀⠉⡏⣆⠈⡀⠀⠀

2023-12-19 02:27:14
int i, j, n;
cin >> n;
for(i = n; i >= 1; i--){
for(j = 1; j <= i; j++){

cout << j <<" ";
}

cout << endl;

}

2023-12-06 04:29:54
https://pynative.com/python-set-quiz/

2023-11-30 11:39:20
#include<iostream>
using namespace std;
int main(){
int a,b,c,p;
cin>>a>>b>>c;
p=a+b+c;
cout<<p<<endl;
}ene

Last edit: 2023-11-30 11:42:20

2023-11-30 10:20:37
uilseegay.aternos.me:31657

2023-11-29 10:40:48
#include<iostream>
using namespace std;
int main(){ int a,b,n,c,d;
cin>>n;
if (n%7==6) cout<<n/7*2+1<<' ';
else cout<<n/7*2<<' ';
if (n%7>1) cout<<n/7*2+2;
else cout<<n/7*2+n%7;
}

2023-11-28 12:30:41
#include <iostream>
using namespace std;
int main() {
int a,n,b,c,x,y,z,k;
cin>>a>>b;
if (a!=2 && b<=28){
cout<<a<<" "<<b+2;
}
if (a==1 && b==29){
cout<<a<<" "<<b+2;
}
if (a==1 && b==30){
cout<<a+1<<" "<<1;
}
if (a==1 && b==31){
cout<<a+1<<" "<<2;
}
if (a==2 && b<=26){
cout<<a<<" "<<b+2;
}
if (a==2 && b==27){
cout<<a+1<<" "<<1;
}
if (a==2 && b==28){
cout<<a+1<<" "<<2;
}
if (a==3 && b==29){
cout<<a<<" "<<b+2;
}
if (a==3 && b==30){
cout<<a+1<<" "<<1;
}
if (a==3 && b==31){
cout<<a+1<<" "<<2;
}
if (a==4 && b==29){
cout<<a+1<<" "<<1;
}
if (a==4 && b==30){
cout<<a+1<<" "<<2;
}
if (a==5 && b==29){
cout<<a<<" "<<b+2;
}
if (a==5 && b==30){
cout<<a+1<<" "<<1;
}
if (a==5 && b==31){
cout<<a+1<<" "<<2;
}
if (a==6 && b==29){
cout<<a+1<<" "<<1;
}
if (a==6 && b==30){
cout<<a+1<<" "<<2;
}
if (a==7 && b==29){
cout<<a<<" "<<b+2;
}
if (a==7 && b==30){
cout<<a+1<<" "<<1;
}
if (a==7 && b==31){
cout<<a+1<<" "<<2;
}
if (a==8 && b==29){
cout<<a<<" "<<b+2;
}
if (a==8 && b==30){
cout<<a+1<<" "<<1;
}
if (a==8 && b==31){
cout<<a+1<<" "<<2;
}
if (a==9 && b==29){
cout<<a+1<<" "<<1;
}
if (a==9 && b==30){
cout<<a+1<<" "<<2;
}
if (a==10 && b==29){
cout<<a<<" "<<b+2;
}
if (a==10 && b==30){
cout<<a+1<<" "<<1;
}
if (a==10 && b==31){
cout<<a+1<<" "<<2;
}
if (a==11 && b==29){
cout<<a+1<<" "<<1;
}
if (a==11 && b==30){
cout<<a+1<<" "<<2;
}
if (a==12 && b==29){
cout<<a<<" "<<b+2;
}
if (a==12 && b==30){
cout<<1<<" "<<1;
}
if (a==12 && b==31){
cout<<1<<" "<<2;
}
}

2023-11-28 12:13:41
#include<iostream>
using namespace std;
int main(){ int Sn,a,b,c,x,d,w,y,z,i,j,k,l,n=0,m=0; cin>>n>>m>>a>>b;
if (m*a<=b)
cout<<n*a;
else { c=n/m; d=n%m;
cout<<c*b+d*a;
}
}

2023-11-28 10:28:56
uilsjargalisgayBaEq.aternos.me:29619

2023-11-28 10:21:08
#include <iostream>
using namespace std;

main() {
int n,a,b,c,d;
cin>>n;
a=(n%10);
b=(n/10)%10;
c=(n/100);
if ( a==b && b==c && a==c)
cout<<"yes";

else
cout<<"no";

return 0;
}

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7002 - Гурвалжин

Input

Output

Example