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RGB7009 - 2 оронтой тоо

Өгөгдсөн 2 оронтой тооны цифрүүдийн үржвэрийг ол.

Input

2 оронтой тоо өгөгдөнө.

Output

Нэгж ба аравтын орны цифрүүдийн үржвэр.

Example

Input:
27
Output:
14

Нэмсэн:Bataa
Огноо:2011-05-10
Хугацааны хязгаарлалт:0.400s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2021-12-21 02:40:21
#include <stdio.h>
#include<stdlib.h>

main()
{
int a, b, c, d, e, f, g;
scanf("%d",&a);
c=a%100; // 58
f=a%10; //negjiin orniig olchij bgn 8
d=c-f; // 50
e=d/10; //5

printf("%d",f*e);
} ingeed bdohoor blhgui ym. yun dr aldaj bgg min hld uguuch guuys
2021-12-20 10:26:08
#Python
a = list(input())
print(int(a[0]) * int(a[1]))
2021-12-17 03:42:47
#include<stdio.h>
int a,b,c;
main()
{
scanf("%d",&a,&b);
b=a/10;
c=b%10;
printf("%d",c);
}
2021-10-25 04:16:27
...
2021-03-11 11:26:08
hh
2020-10-21 09:20:10
#include <iostream>
using namespace std;

int main()
{
int a,b,c,d;
cin>>a;
b=a/10;
c=a%10;
d=b*c;
cout<<d<<endl;
return 0;
}
2020-10-21 09:19:39
#include <iostream>
using namespace std;

int main()
{
int a,b,c,d;
cin>>a;
b=a/10;
c=a%10;
d=b*c;
cout<<d<<endl;
return 0;
}
genden
2020-09-26 12:00:19
#include <stdio.h>

main()
{
int a, b, c, d, e, f, g;
scanf("%d",&a);
c=a%100;
f=a%10;
d=c-f;
e=d/10;
g=f*e;
printf("%d",g);
}
2020-01-23 05:11:03
#include <cstdio>
int main()
{
int a , b;
scanf("%d",&a);
b = a / 10 % 10;
printf("%d",b);
}
2020-01-23 05:10:49
#include <cstdio>
int main()
{
int a , b , c;
scanf("%d",&a);
b = a / 10;
c = a%10;
printf("%d",c*b);
}
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