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RGB7009 - 2 оронтой тоо

Өгөгдсөн 2 оронтой тооны цифрүүдийн үржвэрийг ол.

Input

2 оронтой тоо өгөгдөнө.

Output

Нэгж ба аравтын орны цифрүүдийн үржвэр.

Example

Input:
27
Output:
14

Нэмсэн:Bataa
Огноо:2011-05-10
Хугацааны хязгаарлалт:0.400s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

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2014-10-09 04:48:11 BODLOGIIN-ANGUUCH 3
yee oilgohgui baigaa muu
2014-10-09 04:37:09 BODLOGIIN-ANGUUCH 2
suga $da nar haha
2014-03-01 06:26:33 Idree
bodh shig bolloo daanj meddeggu eeeeeeeeeeeeeeeee
2014-03-01 06:25:44 TaMuPaa
Bodson hun bnuu ?
2014-02-27 08:34:52 ssbs
bodson hun bn uuuuu
2013-11-20 11:08:25 bulgantamir
hi
2013-10-18 07:13:59 chunaba
huts
2013-05-24 07:21:34 Jiigaa
#include<stdio.h>

main()
{

//freopen("a.in","r",stdin);
//freopen("a.out","w",stdout);

int a,b,c,n;
scanf("%d",&n);

a=(n/10)%10;
b=n%10;

c=a*b;
printf("%d\n",c);

}
2013-05-01 08:55:32 Bulgantamir


Last edit: 2013-05-02 00:51:00
2013-04-03 13:38:15 dolgoon
#include<stdio.h>
#include<stdlib.h>
main()
{
int n,h;
scanf("%d",&n);
h=(n%10)*(n/10%10);
printf("%d",h);
system("pause");
{
#include<stdio.h>
#include<stdlib.h>
main()
{
int n,h;
scanf("%d",&n);
h=(n%10)*(n/10%10);
printf("%d",h);
system("pause");
}

Last edit: 2013-04-03 13:38:34
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