SPOJ.com - Problem RGB7105

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RGB7105 - Нийлбэр 80

Өгөгдсөн 4 тооны 80-аас их тоонуудын нийлбэрийг ол.

Input

Нэг мөрөнд Int төрлийн 4 тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

Нийлбэр.

Example

Input:
85 75 96 69
Output:
181

Submit solution!

Нэмсэн:	Bataa
Огноо:	2011-05-23
Хугацааны хязгаарлалт:	1s
Эх кодын хэмжээний хязгаарлалт:	50000B
Memory limit:	1536MB
Cluster:	Cube (Intel G860)
Програмчлалын хэлүүд:	ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments

2022-06-20 13:26:36
#include <iostream>
using namespace std;

int main() {

// your code here
int a, b, c, d, e, f, n, m;
cin>>a>>b>>c>>d;

if(a <= 80) a=0;
if(b <= 80) b=0;
if(c <= 80) c=0;
if(d <= 80) d=0;

n=a+b+c+d;

cout<<n;
return 0;
}khandma to javhaa

2022-05-20 03:06:27
#include <iostream>
using namespace std;

int main() {
int n=4,s=0,a[5];
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]>80){
s=s+a[i];
}
}
cout<<s;
return 0;
}
hatnaa suga

2022-05-11 09:35:27
#include<stdio.h>
int main()
{
int a,b,c,d,sum,n,v,g,h;
scanf("%d%d%d%d",&a,&b,&c,&d);
if(a>=80)
{
n=a;
}
else
{
n=0;
}
if(b>=80)
{
v=b;
}
else
{
v=0;
}
if(c>=80)
{
g=c;
}
else
{
g=0;
}
if(d>=80)
{
h=d;
}
else
{
h=0;
}

sum=n+v+g+h;
printf("%d",sum);
}//c++

2022-04-02 15:00:43
#include <iostream>
using namespace std;

int main() {

int a, b, c, d, s=0;
cin >> a >> b >> c >> d;
if ( a >= 80 ) s = s + a;
if ( b >= 80 ) s = s + b;
if ( c >= 80 ) s = s + c;
if ( d >= 80 ) s = s + d;
cout << s;
}

2022-03-26 09:44:53
#include <iostream>
using namespace std;

int main(){
int a, b, c, d, e = 80;
cin >> a >> b >> c >> d;

if(a <= e) a = 0;
if(b <= e) b = 0;
if(c <= e) c = 0;
if(d <= e) d = 0;

int res = a + b + c + d;

cout << res ;
return 0;
} // Teneg hun ch haraad oilgono

2022-03-26 09:39:25
#include<bits/stdc++.h>
using namespace std;
int s,a,b,c,d,n=0;
int main (){
cin>>a>>b>>c>>d;
if (a>80) a=a+n;
else if (a<80) a=n;
if (b>80) b=b+n;
else if (b<80) b=n;
if (c>80) c=c+n;
else if (c<80) c=n;
if (d>80) d=d+n;
else if (d<80) d=n;
s=a+b+c+d;
cout<<s;
return 0;
}

2022-03-21 08:57:24
hariuga tavihq bol gae shu

2022-03-07 09:07:17
#include <iostream>
using namespace std;

int main() {

int a,b,c,d,e=0;
cin>>a>>b>>c>>d;
{if(a>79) e=e+a;
else (e=e+0);}
{if(b>79) e=e+b;
else (e=e+0);}
{if(c>79) e=e+c;
else( e=e+0);}
{if(d>79) e=e+d;
else (e=e+0);}
cout<<e<<endl;
return 0;
}

2022-03-01 14:43:56
#include <iostream>
using namespace std;

int main() {

int a, b, c, d, n=0;
cin >> a >> b >> c >> d;
if ( a > 80 ) n = n + a;
else if ( a < 80 ) n = n;
if ( b > 80 ) n = n + b;
else if ( b < 80 ) n = n;
if ( c > 80 ) n = n + c;
else if ( c < 80 ) n = n;
if ( d > 80 ) n = n + d;
else if ( d < 80 ) n = n;
cout << n << endl;

return 0;
} life

2022-03-01 08:31:21
#include <bits/stdc++.h>
using namespace std;
main(){
int a,b,c,d,g=0;
cin>>a>>b>>c>>d;
if(a>80)g+=a;
if(b>80)g+=b;
if(c>80)g+=c;
if(d>80)g+=d;

cout<<g;
}
for bambuk

АЛГОРИТМЫН ЦАГААН ТОЛГОЙ

RGB7105 - Нийлбэр 80

Input

Output

Example