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RGB7105 - Нийлбэр 80

Өгөгдсөн 4 тооны 80-аас их тоонуудын нийлбэрийг ол.

Input

Нэг мөрөнд Int төрлийн 4 тоо зайгаар тусгаарлагдан өгөгдөнө.

Output

Нийлбэр.

Example

Input:
85 75 96 69
Output:
181

Нэмсэн:Bataa
Огноо:2011-05-23
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 BASH BF C NCSHARP CSHARP C++ 4.3.2 CPP C99 CLPS LISP sbcl LISP clisp D ERL FORTRAN HASK ICON ICK JAVA JS-RHINO JULIA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYPY3 PYTHON3 RUBY SCALA SCM guile ST TCL WHITESPACE

hide comments
2020-05-09 07:00:49
haraal edr helhe boliyoo
2020-02-12 02:11:20
herhen code bichij surah ve zovlogoo ogooch guys
2020-01-02 05:58:19
#include<stdio.h>
main(){
int arr[4],i, sum = 0;
for(i = 0; i < 4; i++){
scanf("%d", &arr[i]);
}
for(i = 0; i < 4; i++){
if(arr[i] > 80){
sum = sum + arr[i];
}
}
printf("%d", sum);

}
2019-10-21 04:51:50
ter mbi gomo gd bga sda ooroo gomo
2019-10-21 04:47:35
unjii munjii aajii baajii
2019-10-21 04:47:16
hiceelee taraad shuud harij baildaa zolbin golognuudee
2019-10-21 04:46:46
zogsohgui zogsohgui zogsohgui shagaig huchindeh husel mini zogsohgui hha
2019-10-21 04:46:26
hiceelee hiijii bai ergvv golognuudee
2019-10-21 04:46:01
shagai al shagai al
2019-10-21 03:42:12
#include <bits/stdc++.h>
using namespace std;
main ()
{
int a,b,c,d,e,g=0;
cin>>a>>b>>c>>d;
if(a>80) e=g+a;
if(b>80) e=e+b;
if(c>80) e=e+c;
if(d>80) e=e+d;
cout<<e;
}suga alnuud bodoj sur

Last edit: 2019-10-21 03:42:31
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