FIBOSUM - Fibonacci Sum

The Fibonacci sequence is defined by the following relation:

  • F(0) = 0
  • F(1) = 1
  • F(N) = F(N - 1) + F(N - 2), N >= 2

Your task is very simple. Given two non-negative integers N and M, you have to calculate the sum (F(N) + F(N + 1) + ... + F(M)) mod 1000000007.

Input

The first line contains an integer T (the number of test cases). Then, T lines follow. Each test case consists of a single line with two non-negative integers N and M.

Output

For each test case you have to output a single line containing the answer for the task.

Example

Input:
3
0 3
3 5
10 19

Output:
4
10
10857

Constraints

  • T <= 1000
  • 0 <= N <= M <= 109

Added by:David Gómez
Date:2010-12-04
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:My Own

hide comments
2017-12-24 21:40:59
Learnt matrix expo:
but not tried with f(n+2)-1 :)
2017-12-19 13:08:46
AC in one go:-)
2017-12-14 21:46:06
Matrix exponentiation and f(1)+f(2)+f(3)+... + f(n) = f(n+2)-1 did this :D !!

82nd AC
2017-10-08 19:06:09
Matrix Expo :)
2017-08-23 14:38:43
AC after 1 wa....take care of negative modulus..
2017-07-14 08:55:24
Ac in one go :)
Didn't use Matrix Exponention, Dijkstra's formula was good enough.
And yes negative mod must be taken into account. Thanks @sagnik_66 for the hint
2017-06-23 10:31:35
learn something new !! Matrix exponentiation !!
care about mod !!
2017-06-14 22:46:36
use long long !! Cost me 3WA's
2017-06-11 14:07:35
Why will it ever be negative? @sagnik_66


Last edit: 2017-06-11 14:07:57
2017-06-09 18:23:45
Take care about the negative answers. Just add 1000000007.
Matrix Exponentiation gives answer in 0.0 secs
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