LASTDIG - The last digit

Nestor was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives him two numbers a and b. The problem consist of finding the last digit of the potency of base a and index b. Help Nestor with his problem. You are given two integer numbers: the base a (0 <= a <= 20) and the index b (0 <= b <= 2,147,483,000), a and b both are not 0. You have to find the last digit of ab.

Input

The first line of input contains an integer t, the number of test cases (t <= 30). t test cases follow. For each test case will appear a and b separated by space.

Output

For each test case output an integer per line representing the result.

Example

Input:
2
3 10
6 2

Output: 9 6

Added by:Jose Daniel Rodriguez Morales
Date:2008-12-01
Time limit:1s
Source limit:700B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: GOSU
Resource:Own

hide comments
2020-10-02 06:33:20
used Euler totient function gave the right answer but the compiler not accepting
2020-09-29 06:14:25
compute mod 10 in power funtion
2020-09-22 16:09:19
I am using modular binary exponentiation in this problem but it gives me 700 bytes error and says my program is using much more space then this. please help!!
2020-09-17 16:57:08
I think here "a and b both are not 0" means both are not 0 at the same time.
2020-09-15 07:33:03
Can anyone tell why normal solution is not working?
2020-09-05 16:55:26
I'm new to SPOJ, I've submitted my solution but it crossed the memory limit of 70 bytes. How did you guys manage to solve it in less than 700 bytes?
2020-08-17 09:17:46
Misleading statement 'a and b both are not 0'.
Make sure you account for b = 0 in your code.
2020-08-14 00:24:44
No exponentiation stuff required if you use your brains in last digit patterns of powers :)
0.02 sec 9.1mb with a python code.
2020-07-26 10:25:54
calculate (a^b)mod 10 using binary exponentiation .
2020-07-25 17:50:47
i cannot what is mistake in code please help
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